What is the general solution for sin(9x+40)=cos(-5x+42) ?

The general solution for sin(9x+40)=cos(-5x+42) is x=(4pin+pi-164)/8 ,x=(4pin+4+pi)/(28)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(9x+40)=cos(-5x+42)

sin (9 x + 40) = cos (- 5 x + 42)

x = \frac{4 πn + π - 164}{8}, x = \frac{4 πn + 4 + π}{28}

Solution steps

sin (9 x + 40) = cos (- 5 x + 42)

Rewrite using trig identities

sin (9 x + 40) = sin (\frac{π}{2} - (- 5 x + 42))

Apply trig inverse properties

9 x + 40 = \frac{π}{2} - (- 5 x + 42) + 2 πn, 9 x + 40 = π - (\frac{π}{2} - (- 5 x + 42)) + 2 πn

9 x + 40 = \frac{π}{2} - (- 5 x + 42) + 2 πn : x = \frac{4 πn + π - 164}{8}

9 x + 40 = π - (\frac{π}{2} - (- 5 x + 42)) + 2 πn : x = \frac{4 πn + 4 + π}{28}

x = \frac{4 πn + π - 164}{8}, x = \frac{4 πn + 4 + π}{28}

sin^{2} (a) = - \frac{( 5 11 )}{( 18 )}

3.87 sin (\frac{2 π ( t + 101.75 )}{365}) + 11.7 = 14

2 sin (2 x) = 3, 0 \leq x \leq 2 π

cosh (2 x) + sinh^{2} (x) - 13 sinh (x) = - 3

sin (3 x - \frac{π}{4}) = 1

What is the general solution for sin(9x+40)=cos(-5x+42) ?
The general solution for sin(9x+40)=cos(-5x+42) is x=(4pin+pi-164)/8 ,x=(4pin+4+pi)/(28)