What is the general solution for 2sin(2x)=sqrt(3),0<= x<= 2pi ?

The general solution for 2sin(2x)=sqrt(3),0<= x<= 2pi is x= pi/6 ,x= pi/3 ,x=(7pi)/6 ,x=(4pi)/3

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2sin(2x)=sqrt(3),0<= x<= 2pi

2 sin (2 x) = 3, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{π}{3}, x = \frac{7 π}{6}, x = \frac{4 π}{3}

Solution steps

2 sin (2 x) = 3, 0 \leq x \leq 2 π

Divide both sides by

2

sin (2 x) = \frac{3}{2}

General solutions for

sin (2 x) = \frac{3}{2}

2 x = \frac{π}{3} + 2 πn, 2 x = \frac{2 π}{3} + 2 πn

Solve

2 x = \frac{π}{3} + 2 πn : x = \frac{π}{6} + πn

Solve

2 x = \frac{2 π}{3} + 2 πn : x = \frac{π}{3} + πn

x = \frac{π}{6} + πn, x = \frac{π}{3} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{π}{3}, x = \frac{7 π}{6}, x = \frac{4 π}{3}

cosh (2 x) + sinh^{2} (x) - 13 sinh (x) = - 3

sin (3 x - \frac{π}{4}) = 1

\frac{1 - tan ^{2} ( A )}{1 + tan ^{2} ( A )} = 1

sin (2 x) - 0.8 = 0

tan (a) = \frac{15}{7}, sin (a)

What is the general solution for 2sin(2x)=sqrt(3),0<= x<= 2pi ?
The general solution for 2sin(2x)=sqrt(3),0<= x<= 2pi is x= pi/6 ,x= pi/3 ,x=(7pi)/6 ,x=(4pi)/3