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受欢迎的三角函数 >

3.87sin((2pi(t+101.75))/(365))+11.7=14

解答

3.87 sin (\frac{2 π ( t + 101.75 )}{365}) + 11.7 = 14

解答

t = \frac{365 \cdot 0.63641 \dots}{2 π} + 365 n - 101.75, t = \frac{365}{2} - \frac{365 \cdot 0.63641 \dots}{2 π} + 365 n - 101.75

+1

度数

t = - 3711.60484 \dots^{\circ} + 20912.95952 \dots^{\circ} n, t = 2508.39347 \dots^{\circ} + 20912.95952 \dots^{\circ} n

求解步骤

3.87 sin (\frac{2 π ( t + 101.75 )}{365}) + 11.7 = 14

在两边乘以

100

3.87 sin (\frac{2 π ( t + 101.75 )}{365}) + 11.7 = 14

To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere are

2

digits to the right of the decimal point, therefore multiply by

100

3.87 sin (\frac{2 π ( t + 101.75 )}{365}) \cdot 100 + 11.7 \cdot 100 = 14 \cdot 100

整理后得

387 sin (\frac{2 π ( t + 101.75 )}{365}) + 1170 = 1400

387 sin (\frac{2 π ( t + 101.75 )}{365}) + 1170 = 1400

将

1170

到右边

387 sin (\frac{2 π ( t + 101.75 )}{365}) + 1170 = 1400

两边减去

1170

387 sin (\frac{2 π ( t + 101.75 )}{365}) + 1170 - 1170 = 1400 - 1170

化简

387 sin (\frac{2 π ( t + 101.75 )}{365}) = 230

387 sin (\frac{2 π ( t + 101.75 )}{365}) = 230

两边除以

387

387 sin (\frac{2 π ( t + 101.75 )}{365}) = 230

两边除以

387

\frac{387 sin ( \frac{2 π ( t + 101.75 )}{365} )}{387} = \frac{230}{387}

化简

sin (\frac{2 π ( t + 101.75 )}{365}) = \frac{230}{387}

sin (\frac{2 π ( t + 101.75 )}{365}) = \frac{230}{387}

使用反三角函数性质

sin (\frac{2 π ( t + 101.75 )}{365}) = \frac{230}{387}

sin (\frac{2 π ( t + 101.75 )}{365}) = \frac{230}{387}

的通解

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

\frac{2 π ( t + 101.75 )}{365} = arcsin (\frac{230}{387}) + 2 πn, \frac{2 π ( t + 101.75 )}{365} = π - arcsin (\frac{230}{387}) + 2 πn

\frac{2 π ( t + 101.75 )}{365} = arcsin (\frac{230}{387}) + 2 πn, \frac{2 π ( t + 101.75 )}{365} = π - arcsin (\frac{230}{387}) + 2 πn

解

\frac{2 π ( t + 101.75 )}{365} = arcsin (\frac{230}{387}) + 2 πn : t = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

\frac{2 π ( t + 101.75 )}{365} = arcsin (\frac{230}{387}) + 2 πn

在两边乘以

365

\frac{2 π ( t + 101.75 )}{365} = arcsin (\frac{230}{387}) + 2 πn

在两边乘以

365

\frac{365 \cdot 2 π ( t + 101.75 )}{365} = 365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn

化简

\frac{365 \cdot 2 π ( t + 101.75 )}{365} = 365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn

化简

\frac{365 \cdot 2 π ( t + 101.75 )}{365} : 2 π (t + 101.75)

\frac{365 \cdot 2 π ( t + 101.75 )}{365}

数字相乘:

365 \cdot 2 = 730

= \frac{730 π ( t + 101.75 )}{365}

数字相除:

\frac{730}{365} = 2

= 2 π (t + 101.75)

化简

365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn : 365 arcsin (\frac{230}{387}) + 730 πn

365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn

数字相乘:

365 \cdot 2 = 730

= 365 arcsin (\frac{230}{387}) + 730 πn

2 π (t + 101.75) = 365 arcsin (\frac{230}{387}) + 730 πn

2 π (t + 101.75) = 365 arcsin (\frac{230}{387}) + 730 πn

2 π (t + 101.75) = 365 arcsin (\frac{230}{387}) + 730 πn

两边除以

2 π

2 π (t + 101.75) = 365 arcsin (\frac{230}{387}) + 730 πn

两边除以

2 π

\frac{2 π ( t + 101.75 )}{2 π} = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

化简

\frac{2 π ( t + 101.75 )}{2 π} = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

化简

\frac{2 π ( t + 101.75 )}{2 π} : t + 101.75

\frac{2 π ( t + 101.75 )}{2 π}

数字相除:

\frac{2}{2} = 1

= \frac{π ( t + 101.75 )}{π}

约分:

π

= t + 101.75

化简

\frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π} : \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

\frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

消掉

\frac{730 πn}{2 π} : 365 n

\frac{730 πn}{2 π}

消掉

\frac{730 πn}{2 π} : 365 n

\frac{730 πn}{2 π}

数字相除:

\frac{730}{2} = 365

= \frac{365 πn}{π}

约分:

π

= 365 n

= 365 n

= \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

t + 101.75 = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

t + 101.75 = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

t + 101.75 = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

将

101.75

到右边

t + 101.75 = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

两边减去

101.75

t + 101.75 - 101.75 = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

化简

t = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

t = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

解

\frac{2 π ( t + 101.75 )}{365} = π - arcsin (\frac{230}{387}) + 2 πn : t = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

\frac{2 π ( t + 101.75 )}{365} = π - arcsin (\frac{230}{387}) + 2 πn

在两边乘以

365

\frac{2 π ( t + 101.75 )}{365} = π - arcsin (\frac{230}{387}) + 2 πn

在两边乘以

365

\frac{365 \cdot 2 π ( t + 101.75 )}{365} = 365 π - 365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn

化简

\frac{365 \cdot 2 π ( t + 101.75 )}{365} = 365 π - 365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn

化简

\frac{365 \cdot 2 π ( t + 101.75 )}{365} : 2 π (t + 101.75)

\frac{365 \cdot 2 π ( t + 101.75 )}{365}

数字相乘:

365 \cdot 2 = 730

= \frac{730 π ( t + 101.75 )}{365}

数字相除:

\frac{730}{365} = 2

= 2 π (t + 101.75)

化简

365 π - 365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn : 365 π - 365 arcsin (\frac{230}{387}) + 730 πn

365 π - 365 arcsin (\frac{230}{387}) + 365 \cdot 2 πn

数字相乘:

365 \cdot 2 = 730

= 365 π - 365 arcsin (\frac{230}{387}) + 730 πn

2 π (t + 101.75) = 365 π - 365 arcsin (\frac{230}{387}) + 730 πn

2 π (t + 101.75) = 365 π - 365 arcsin (\frac{230}{387}) + 730 πn

2 π (t + 101.75) = 365 π - 365 arcsin (\frac{230}{387}) + 730 πn

两边除以

2 π

2 π (t + 101.75) = 365 π - 365 arcsin (\frac{230}{387}) + 730 πn

两边除以

2 π

\frac{2 π ( t + 101.75 )}{2 π} = \frac{365 π}{2 π} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

化简

\frac{2 π ( t + 101.75 )}{2 π} = \frac{365 π}{2 π} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

化简

\frac{2 π ( t + 101.75 )}{2 π} : t + 101.75

\frac{2 π ( t + 101.75 )}{2 π}

数字相除:

\frac{2}{2} = 1

= \frac{π ( t + 101.75 )}{π}

约分:

π

= t + 101.75

化简

\frac{365 π}{2 π} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π} : \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

\frac{365 π}{2 π} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

消掉

\frac{365 π}{2 π} : \frac{365}{2}

\frac{365 π}{2 π}

约分:

π

= \frac{365}{2}

= \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + \frac{730 πn}{2 π}

消掉

\frac{730 πn}{2 π} : 365 n

\frac{730 πn}{2 π}

消掉

\frac{730 πn}{2 π} : 365 n

\frac{730 πn}{2 π}

数字相除:

\frac{730}{2} = 365

= \frac{365 πn}{π}

约分:

π

= 365 n

= 365 n

= \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

t + 101.75 = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

t + 101.75 = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

t + 101.75 = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

将

101.75

到右边

t + 101.75 = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n

两边减去

101.75

t + 101.75 - 101.75 = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

化简

t = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

t = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

t = \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75, t = \frac{365}{2} - \frac{365 arcsin ( \frac{230}{387} )}{2 π} + 365 n - 101.75

以小数形式表示解

t = \frac{365 \cdot 0.63641 \dots}{2 π} + 365 n - 101.75, t = \frac{365}{2} - \frac{365 \cdot 0.63641 \dots}{2 π} + 365 n - 101.75

作图

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