What is the axis y=2*x^2+x-2 ?

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axis y=2*x^2+x-2

axis

y = 2 \cdot x^{2} + x - 2

x = - \frac{1}{4}

Solution steps

y = 2 x^{2} + x - 2

Rewrite

y = 2 x^{2} + x - 2

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{17}{8})) = (x - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, - \frac{17}{8}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{1}{4}

- 2 x^{2} - 4 x + y + 70 = 0

y = - 2 (x - 2)^{2} + 7

y > x^{2} - 3

y = x^{2} + 6 x + 5

y = 0.09 x^{2} + 16 x + 350