What is the axis y>x^2-3 ?

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axis y>x^2-3

axis

y > x^{2} - 3

x = 0

Solution steps

y > x^{2} - 3

Rewrite

y > x^{2} - 3

in the standard form:

4 \cdot \frac{1}{4} (y - (- 3)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 3), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} + 6 x + 5

y = 0.09 x^{2} + 16 x + 350

y = - x^{2} + 8 x - 7

y = x^{2} - 6 x + 9

y = - (x - 4)^{2} - 24