What is the axis y=0.09x^2+16x+350 ?

The axis y=0.09x^2+16x+350 is x=-88.88888…

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axis y=0.09x^2+16x+350

axis

y = 0.09 x^{2} + 16 x + 350

x = - 88.88888 \dots

Solution steps

y = 0.09 x^{2} + 16 x + 350

Rewrite

y = 0.09 x^{2} + 16 x + 350

in the standard form

4 \cdot 2.77777 \dots (y - (- 361.11111 \dots)) = (x - (- 88.88888 \dots))^{2}

Therefore parabola properties are:

(h, k) = (- 88.88888 \dots, - 361.11111 \dots), p = 2.77777 \dots

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 88.88888 \dots

y = - x^{2} + 8 x - 7

y = x^{2} - 6 x + 9

y = - (x - 4)^{2} - 24

y = - 0.05 x^{2} + 10

y^{2} + 24 y - 9 x + 225 = 0