What is the axis (3x-2)^2=84y-112 ?

The axis (3x-2)^2=84y-112 is x= 2/3

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axis (3x-2)^2=84y-112

axis

(3 x - 2)^{2} = 84 y - 112

x = \frac{2}{3}

Solution steps

(3 x - 2)^{2} = 84 y - 112

Rewrite

(3 x - 2)^{2} = 84 y - 112

in the standard form:

4 \cdot \frac{7}{3} (y - \frac{4}{3}) = (x - \frac{2}{3})^{2}

Therefore parabola properties are:

(h, k) = (\frac{2}{3}, \frac{4}{3}), p = \frac{7}{3}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{2}{3}

y = 4 x^{2} - 6 x

y = 3 x^{2} - 30 x - 2

y = - x^{2} + 4 x - 3

y^{2} - 12 y - 4 x = - 28

25 x^{2} - 10 x - 200 y - 119 = 0