What is the axis y^2-12y-4x=-28 ?

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axis y^2-12y-4x=-28

axis

y^{2} - 12 y - 4 x = - 28

y = 6

Solution steps

y^{2} - 12 y - 4 x = - 28

Rewrite

y^{2} - 12 y - 4 x = - 28

in the standard form

4 \cdot 1 \cdot (x - (- 2)) = (y - 6)^{2}

Therefore parabola properties are:

(h, k) = (- 2, 6), p = 1

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 6

25 x^{2} - 10 x - 200 y - 119 = 0

y = x^{2} - 21 x - 4

y = - x^{2} + 150 x - 2000

y = - 3 x^{2} - 12 x - 5

y = x^{2} - 5