What is the axis y^2+24y-9x+225=0 ?

The axis y^2+24y-9x+225=0 is y=-12

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axis y^2+24y-9x+225=0

axis

y^{2} + 24 y - 9 x + 225 = 0

y = - 12

Solution steps

y^{2} + 24 y - 9 x + 225 = 0

Rewrite

y^{2} + 24 y - 9 x + 225 = 0

in the standard form

4 \cdot \frac{9}{4} (x - 9) = (y - (- 12))^{2}

Therefore parabola properties are:

(h, k) = (9, - 12), p = \frac{9}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 12

(3 x - 2)^{2} = 84 y - 112

y = 4 x^{2} - 6 x

y = 3 x^{2} - 30 x - 2

y = - x^{2} + 4 x - 3

y^{2} - 12 y - 4 x = - 28