What is the axis y=x^2+6x+5 ?

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axis y=x^2+6x+5

axis

y = x^{2} + 6 x + 5

x = - 3

Solution steps

y = x^{2} + 6 x + 5

Rewrite

y = x^{2} + 6 x + 5

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 3

y = 0.09 x^{2} + 16 x + 350

y = - x^{2} + 8 x - 7

y = x^{2} - 6 x + 9

y = - (x - 4)^{2} - 24

y = - 0.05 x^{2} + 10