What is the axis y=-2(x-2)^2+7 ?

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axis y=-2(x-2)^2+7

axis

y = - 2 (x - 2)^{2} + 7

x = 2

Solution steps

y = - 2 (x - 2)^{2} + 7

Rewrite

y = - 2 (x - 2)^{2} + 7

in the standard form:

4 (- \frac{1}{8}) (y - 7) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 7), p = - \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y > x^{2} - 3

y = x^{2} + 6 x + 5

y = 0.09 x^{2} + 16 x + 350

y = - x^{2} + 8 x - 7

y = x^{2} - 6 x + 9