What is the axis-2x^2-4x+y+70=0 ?

The axis-2x^2-4x+y+70=0 is x=-1

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axis-2x^2-4x+y+70=0

axis

- 2 x^{2} - 4 x + y + 70 = 0

x = - 1

Solution steps

- 2 x^{2} - 4 x + y + 70 = 0

Rewrite

- 2 x^{2} - 4 x + y + 70 = 0

in the standard form

4 \cdot \frac{1}{8} (y - (- 72)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 72), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = - 2 (x - 2)^{2} + 7

y > x^{2} - 3

y = x^{2} + 6 x + 5

y = 0.09 x^{2} + 16 x + 350

y = - x^{2} + 8 x - 7