What is the extreme f(x)=(x^2+11)(9-x^2) ?

The extreme f(x)=(x^2+11)(9-x^2) is Maximum(0,99)

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extreme f(x)=(x^2+11)(9-x^2)

extreme points

f (x) = (x^{2} + 11) (9 - x^{2})

Maximum (0, 99)

Solution steps

f^{'} (x) = - 4 x (x^{2} + 1)

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = 0

into

(x^{2} + 11) (9 - x^{2}) : 99

Maximum (0, 99)

What is the extreme f(x)=(x^2+11)(9-x^2) ?
The extreme f(x)=(x^2+11)(9-x^2) is Maximum(0,99)