What is the extreme y=100+1/2 x+(1800)/x ?

The extreme y=100+1/2 x+(1800)/x is Maximum(-60,40),Minimum(60,160)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme y=100+1/2 x+(1800)/x

extreme points

y = 100 + \frac{1}{2} x + \frac{1800}{x}

Maximum (- 60, 40), Minimum (60, 160)

Solution steps

f^{'} (x) = - \frac{1800}{x ^{2}} + \frac{1}{2}

Find intervals:

Increasing

: - \infty < x < - 60,

Decreasing

: - 60 < x < 0,

Decreasing

: 0 < x < 60,

Increasing

: 60 < x < \infty

Plug

x = - 60

into

100 + \frac{1}{2} x + \frac{1800}{x} : 40

Maximum (- 60, 40)

Plug

x = 60

into

100 + \frac{1}{2} x + \frac{1800}{x} : 160

Minimum (60, 160)

Maximum (- 60, 40), Minimum (60, 160)

What is the extreme y=100+1/2 x+(1800)/x ?
The extreme y=100+1/2 x+(1800)/x is Maximum(-60,40),Minimum(60,160)