What is the general solution for sin^2(x)+2cos^2(x)=2 ?

The general solution for sin^2(x)+2cos^2(x)=2 is x=2pin,x=pi+2pin

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sin^2(x)+2cos^2(x)=2

sin^{2} (x) + 2 cos^{2} (x) = 2

x = 2 πn, x = π + 2 πn

Solution steps

sin^{2} (x) + 2 cos^{2} (x) = 2

Subtract

2

from both sides

sin^{2} (x) + 2 cos^{2} (x) - 2 = 0

Rewrite using trig identities

- sin^{2} (x) = 0

Divide both sides by

- 1

sin (x) = 0

General solutions for

sin (x) = 0

x = 0 + 2 πn, x = π + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 2 πn, x = π + 2 πn

x, cos^{2} (x) + cos^{2} (y) cos^{2} (z) = 1

cos (5 x) + cos (x) = 0

x, f = cos^{2} (x)

cos^{2} (x) - 2 cos (x) = - 1

5 cos^{2} (x) + 3 cos (x) - 2 = 0

What is the general solution for sin^2(x)+2cos^2(x)=2 ?
The general solution for sin^2(x)+2cos^2(x)=2 is x=2pin,x=pi+2pin