What is the general solution for cos^3(x)=66 ?

The general solution for cos^3(x)=66 is No Solution for x\in\mathbb{R}

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Popular Trigonometry >

cos^3(x)=66

Solution

cos^{3} (x) = 66

Solution

No Solution for x \in R

Solution steps

cos^{3} (x) = 66

Solve by substitution

cos^{3} (x) = 66

Let:

cos (x) = u

u^{3} = 66

u^{3} = 66 : u = 366, u = - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2}, u = - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2}

u^{3} = 66

For

x^{3} = f (a)

the solutions are

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

u = 366, u = 366 \frac{- 1 + 3 i}{2}, u = 366 \frac{- 1 - 3 i}{2}

Simplify

366 \frac{- 1 + 3 i}{2} : - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2}

366 \frac{- 1 + 3 i}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 1 + 3 i ) 3 66}{2}

Factor

366 : 3233311

Factor

66 = 2 \cdot 3 \cdot 11

= 3 2 \cdot 3 \cdot 11

Apply radical rule:

n ab = n a n b

= 3233311

= \frac{3 2 3 3 3 11 ( - 1 + 3 i )}{2}

Cancel

\frac{( - 1 + 3 i ) 3 2 3 3 3 11}{2} : \frac{3 3 3 11 ( - 1 + 3 i )}{2 ^{\frac{2}{3}}}

\frac{( - 1 + 3 i ) 3 2 3 3 3 11}{2}

Apply radical rule:

n a = a^{\frac{1}{n}}

32 = 2^{\frac{1}{3}}

= \frac{2 ^{\frac{1}{3}} 3 3 3 11 ( - 1 + 3 i )}{2}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{3}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{3}}}

= \frac{3 3 3 11 ( - 1 + 3 i )}{2 ^{1 - \frac{1}{3}}}

Subtract the numbers:

1 - \frac{1}{3} = \frac{2}{3}

= \frac{3 3 3 11 ( - 1 + 3 i )}{2 ^{\frac{2}{3}}}

= \frac{3 3 3 11 ( - 1 + 3 i )}{2 ^{\frac{2}{3}}}

Simplify

33311 (- 1 + 3 i) : 333 (- 1 + 3 i)

33311 (- 1 + 3 i)

Apply radical rule:

n a n b = n a \cdot b

33311 = 3 3 \cdot 11

= (- 1 + 3 i) 3 3 \cdot 11

Multiply the numbers:

3 \cdot 11 = 33

= 333 (- 1 + 3 i)

= \frac{3 33 ( - 1 + 3 i )}{2 ^{\frac{2}{3}}}

Expand

333 (- 1 + 3 i) : - 333 + 311 \cdot 3^{\frac{5}{6}} i

333 (- 1 + 3 i)

Apply the distributive law:

a (b + c) = ab + a c

a = 333, b = - 1, c = 3 i

= 333 (- 1) + 3333 i

Apply minus-plus rules

+ (- a) = - a

= - 1 \cdot 333 + 3333 i

Simplify

- 1 \cdot 333 + 3333 i : - 333 + 311 \cdot 3^{\frac{5}{6}} i

- 1 \cdot 333 + 3333 i

1 \cdot 333 = 333

1 \cdot 333

Multiply:

1 \cdot 333 = 333

= 333

3333 i = 311 \cdot 3^{\frac{5}{6}} i

3333 i

Factor integer

33 = 3 \cdot 11

= 3 3 \cdot 11 3 i

Apply radical rule:

n ab = n a n b

3 3 \cdot 11 = 33311

= 333113 i

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

333 = 3^{\frac{1}{3}} \cdot 3^{\frac{1}{2}} = 3^{\frac{1}{3} + \frac{1}{2}}

= 311 \cdot 3^{\frac{1}{3} + \frac{1}{2}} i

3^{\frac{1}{3} + \frac{1}{2}} = 3^{\frac{5}{6}}

3^{\frac{1}{3} + \frac{1}{2}}

Join

\frac{1}{3} + \frac{1}{2} : \frac{5}{6}

\frac{1}{3} + \frac{1}{2}

Least Common Multiplier of

3, 2 : 6

3, 2

Least Common Multiplier (LCM)

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Multiply each factor the greatest number of times it occurs in either

3

2

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{1}{3} :

multiply the denominator and numerator by

2

\frac{1}{3} = \frac{1 \cdot 2}{3 \cdot 2} = \frac{2}{6}

For

\frac{1}{2} :

multiply the denominator and numerator by

3

\frac{1}{2} = \frac{1 \cdot 3}{2 \cdot 3} = \frac{3}{6}

= \frac{2}{6} + \frac{3}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 3}{6}

Add the numbers:

2 + 3 = 5

= \frac{5}{6}

= 3^{\frac{5}{6}}

= 311 \cdot 3^{\frac{5}{6}} i

= - 333 + 311 \cdot 3^{\frac{5}{6}} i

= - 333 + 311 \cdot 3^{\frac{5}{6}} i

= \frac{- 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

Rationalize

\frac{- 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}} : \frac{3 2 ( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

\frac{- 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

Multiply by the conjugate

\frac{3 2}{3 2}

= \frac{( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i ) 3 2}{2 ^{\frac{2}{3}} 3 2}

2^{\frac{2}{3}} 32 = 2

2^{\frac{2}{3}} 32

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{2}{3}} 32 = 2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}} = 2^{\frac{2}{3} + \frac{1}{3}}

= 2^{\frac{2}{3} + \frac{1}{3}}

Join

\frac{2}{3} + \frac{1}{3} : 1

\frac{2}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= \frac{3 2 ( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

= \frac{3 2 ( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

Rewrite

\frac{3 2 ( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

in standard complex form:

- 3 \frac{33}{4} + \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2} i

\frac{3 2 ( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

Apply radical rule:

n a = a^{\frac{1}{n}}

32 = 2^{\frac{1}{3}}

= \frac{2 ^{\frac{1}{3}} ( - 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{3}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{3}}}

= \frac{- 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{1 - \frac{1}{3}}}

Subtract the numbers:

1 - \frac{1}{3} = \frac{2}{3}

= \frac{- 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 33 + 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}} = - \frac{3 33}{2 ^{\frac{2}{3}}} + \frac{3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

= - \frac{3 33}{2 ^{\frac{2}{3}}} + \frac{3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

\frac{3 33}{2 ^{\frac{2}{3}}} = 3 \frac{33}{4}

\frac{3 33}{2 ^{\frac{2}{3}}}

333 = 3 3^{\frac{1}{3}}

= \frac{3 3 ^{\frac{1}{3}}}{2 ^{\frac{2}{3}}}

Combine same powers :

\frac{x ^{\frac{a}{m}}}{y ^{\frac{b}{m}}} = m \frac{x ^{a}}{y ^{b}}

= 3 \frac{33}{2 ^{2}}

2^{2} = 4

= 3 \frac{33}{4}

= - 3 \frac{33}{4} + \frac{3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

\frac{3 11 \cdot 3 ^{\frac{5}{6}}}{2 ^{\frac{2}{3}}} = \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2}

\frac{3 11 \cdot 3 ^{\frac{5}{6}}}{2 ^{\frac{2}{3}}}

Multiply by the conjugate

\frac{3 2}{3 2}

= \frac{3 11 \cdot 3 ^{\frac{5}{6}} 3 2}{2 ^{\frac{2}{3}} 3 2}

311 \cdot 3^{\frac{5}{6}} 32 = 322 \cdot 3^{\frac{5}{6}}

311 \cdot 3^{\frac{5}{6}} 32

Apply radical rule:

n a n b = n a \cdot b

31132 = 3 11 \cdot 2

= 3^{\frac{5}{6}} 3 11 \cdot 2

Multiply the numbers:

11 \cdot 2 = 22

= 322 \cdot 3^{\frac{5}{6}}

2^{\frac{2}{3}} 32 = 2

2^{\frac{2}{3}} 32

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{2}{3}} 32 = 2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}} = 2^{\frac{2}{3} + \frac{1}{3}}

= 2^{\frac{2}{3} + \frac{1}{3}}

Join

\frac{2}{3} + \frac{1}{3} : 1

\frac{2}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2}

= - 3 \frac{33}{4} + \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2} i

= - 3 \frac{33}{4} + \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2} i

Simplify

366 \frac{- 1 - 3 i}{2} : - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2}

366 \frac{- 1 - 3 i}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - 1 - 3 i ) 3 66}{2}

Factor

366 : 3233311

Factor

66 = 2 \cdot 3 \cdot 11

= 3 2 \cdot 3 \cdot 11

Apply radical rule:

n ab = n a n b

= 3233311

= \frac{3 2 3 3 3 11 ( - 1 - 3 i )}{2}

Cancel

\frac{( - 1 - 3 i ) 3 2 3 3 3 11}{2} : \frac{3 3 3 11 ( - 1 - 3 i )}{2 ^{\frac{2}{3}}}

\frac{( - 1 - 3 i ) 3 2 3 3 3 11}{2}

Apply radical rule:

n a = a^{\frac{1}{n}}

32 = 2^{\frac{1}{3}}

= \frac{2 ^{\frac{1}{3}} 3 3 3 11 ( - 1 - 3 i )}{2}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{3}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{3}}}

= \frac{3 3 3 11 ( - 1 - 3 i )}{2 ^{1 - \frac{1}{3}}}

Subtract the numbers:

1 - \frac{1}{3} = \frac{2}{3}

= \frac{3 3 3 11 ( - 1 - 3 i )}{2 ^{\frac{2}{3}}}

= \frac{3 3 3 11 ( - 1 - 3 i )}{2 ^{\frac{2}{3}}}

Simplify

33311 (- 1 - 3 i) : 333 (- 1 - 3 i)

33311 (- 1 - 3 i)

Apply radical rule:

n a n b = n a \cdot b

33311 = 3 3 \cdot 11

= (- 1 - 3 i) 3 3 \cdot 11

Multiply the numbers:

3 \cdot 11 = 33

= 333 (- 1 - 3 i)

= \frac{3 33 ( - 1 - 3 i )}{2 ^{\frac{2}{3}}}

Expand

333 (- 1 - 3 i) : - 333 - 311 \cdot 3^{\frac{5}{6}} i

333 (- 1 - 3 i)

Apply the distributive law:

a (b - c) = ab - a c

a = 333, b = - 1, c = 3 i

= 333 (- 1) - 3333 i

Apply minus-plus rules

+ (- a) = - a

= - 1 \cdot 333 - 3333 i

Simplify

- 1 \cdot 333 - 3333 i : - 333 - 311 \cdot 3^{\frac{5}{6}} i

- 1 \cdot 333 - 3333 i

1 \cdot 333 = 333

1 \cdot 333

Multiply:

1 \cdot 333 = 333

= 333

3333 i = 311 \cdot 3^{\frac{5}{6}} i

3333 i

Factor integer

33 = 3 \cdot 11

= 3 3 \cdot 11 3 i

Apply radical rule:

n ab = n a n b

3 3 \cdot 11 = 33311

= 333113 i

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

333 = 3^{\frac{1}{3}} \cdot 3^{\frac{1}{2}} = 3^{\frac{1}{3} + \frac{1}{2}}

= 311 \cdot 3^{\frac{1}{3} + \frac{1}{2}} i

3^{\frac{1}{3} + \frac{1}{2}} = 3^{\frac{5}{6}}

3^{\frac{1}{3} + \frac{1}{2}}

Join

\frac{1}{3} + \frac{1}{2} : \frac{5}{6}

\frac{1}{3} + \frac{1}{2}

Least Common Multiplier of

3, 2 : 6

3, 2

Least Common Multiplier (LCM)

Prime factorization of

3 : 3

3

3

is a prime number, therefore no factorization is possible

= 3

Prime factorization of

2 : 2

2

2

is a prime number, therefore no factorization is possible

= 2

Multiply each factor the greatest number of times it occurs in either

3

2

= 3 \cdot 2

Multiply the numbers:

3 \cdot 2 = 6

= 6

Adjust Fractions based on the LCM

Multiply each numerator by the same amount needed to multiply its

corresponding denominator to turn it into the LCM

6

For

\frac{1}{3} :

multiply the denominator and numerator by

2

\frac{1}{3} = \frac{1 \cdot 2}{3 \cdot 2} = \frac{2}{6}

For

\frac{1}{2} :

multiply the denominator and numerator by

3

\frac{1}{2} = \frac{1 \cdot 3}{2 \cdot 3} = \frac{3}{6}

= \frac{2}{6} + \frac{3}{6}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 3}{6}

Add the numbers:

2 + 3 = 5

= \frac{5}{6}

= 3^{\frac{5}{6}}

= 311 \cdot 3^{\frac{5}{6}} i

= - 333 - 311 \cdot 3^{\frac{5}{6}} i

= - 333 - 311 \cdot 3^{\frac{5}{6}} i

= \frac{- 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

Rationalize

\frac{- 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}} : \frac{3 2 ( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

\frac{- 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

Multiply by the conjugate

\frac{3 2}{3 2}

= \frac{( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i ) 3 2}{2 ^{\frac{2}{3}} 3 2}

2^{\frac{2}{3}} 32 = 2

2^{\frac{2}{3}} 32

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{2}{3}} 32 = 2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}} = 2^{\frac{2}{3} + \frac{1}{3}}

= 2^{\frac{2}{3} + \frac{1}{3}}

Join

\frac{2}{3} + \frac{1}{3} : 1

\frac{2}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= \frac{3 2 ( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

= \frac{3 2 ( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

Rewrite

\frac{3 2 ( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

in standard complex form:

- 3 \frac{33}{4} - \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2} i

\frac{3 2 ( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

Apply radical rule:

n a = a^{\frac{1}{n}}

32 = 2^{\frac{1}{3}}

= \frac{2 ^{\frac{1}{3}} ( - 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i )}{2}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = \frac{1}{x ^{b - a}}

\frac{2 ^{\frac{1}{3}}}{2 ^{1}} = \frac{1}{2 ^{1 - \frac{1}{3}}}

= \frac{- 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{1 - \frac{1}{3}}}

Subtract the numbers:

1 - \frac{1}{3} = \frac{2}{3}

= \frac{- 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 3 33 - 3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}} = - \frac{3 33}{2 ^{\frac{2}{3}}} - \frac{3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

= - \frac{3 33}{2 ^{\frac{2}{3}}} - \frac{3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

\frac{3 33}{2 ^{\frac{2}{3}}} = 3 \frac{33}{4}

\frac{3 33}{2 ^{\frac{2}{3}}}

333 = 3 3^{\frac{1}{3}}

= \frac{3 3 ^{\frac{1}{3}}}{2 ^{\frac{2}{3}}}

Combine same powers :

\frac{x ^{\frac{a}{m}}}{y ^{\frac{b}{m}}} = m \frac{x ^{a}}{y ^{b}}

= 3 \frac{33}{2 ^{2}}

2^{2} = 4

= 3 \frac{33}{4}

= - 3 \frac{33}{4} - \frac{3 11 \cdot 3 ^{\frac{5}{6}} i}{2 ^{\frac{2}{3}}}

- \frac{3 11 \cdot 3 ^{\frac{5}{6}}}{2 ^{\frac{2}{3}}} = - \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2}

- \frac{3 11 \cdot 3 ^{\frac{5}{6}}}{2 ^{\frac{2}{3}}}

Multiply by the conjugate

\frac{3 2}{3 2}

= - \frac{3 11 \cdot 3 ^{\frac{5}{6}} 3 2}{2 ^{\frac{2}{3}} 3 2}

311 \cdot 3^{\frac{5}{6}} 32 = 322 \cdot 3^{\frac{5}{6}}

311 \cdot 3^{\frac{5}{6}} 32

Apply radical rule:

n a n b = n a \cdot b

31132 = 3 11 \cdot 2

= 3^{\frac{5}{6}} 3 11 \cdot 2

Multiply the numbers:

11 \cdot 2 = 22

= 322 \cdot 3^{\frac{5}{6}}

2^{\frac{2}{3}} 32 = 2

2^{\frac{2}{3}} 32

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

2^{\frac{2}{3}} 32 = 2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}} = 2^{\frac{2}{3} + \frac{1}{3}}

= 2^{\frac{2}{3} + \frac{1}{3}}

Join

\frac{2}{3} + \frac{1}{3} : 1

\frac{2}{3} + \frac{1}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 + 1}{3}

Add the numbers:

2 + 1 = 3

= \frac{3}{3}

Apply rule

\frac{a}{a} = 1

= 1

= 2^{1}

Apply rule

a^{1} = a

= 2

= - \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2}

= - 3 \frac{33}{4} - \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2} i

= - 3 \frac{33}{4} - \frac{3 22 \cdot 3 ^{\frac{5}{6}}}{2} i

u = 366, u = - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2}, u = - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2}

Substitute back

u = cos (x)

cos (x) = 366, cos (x) = - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2}, cos (x) = - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2}

cos (x) = 366, cos (x) = - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2}, cos (x) = - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2}

cos (x) = 366 :

No Solution

cos (x) = 366

- 1 \leq cos (x) \leq 1

No Solution

cos (x) = - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2} :

No Solution

cos (x) = - 3 \frac{33}{4} + i \frac{3 ^{\frac{5}{6}} 3 22}{2}

No Solution

cos (x) = - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2} :

No Solution

cos (x) = - 3 \frac{33}{4} - i \frac{3 ^{\frac{5}{6}} 3 22}{2}

No Solution

Combine all the solutions

No Solution for x \in R

Graph

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Frequently Asked Questions (FAQ)

What is the general solution for cos^3(x)=66 ?
The general solution for cos^3(x)=66 is No Solution for x\in\mathbb{R}