What is the general solution for arctan(1-x)+arctan(1+x)=arctan(1/8) ?

The general solution for arctan(1-x)+arctan(1+x)=arctan(1/8) is x=4,x=-4

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arctan(1-x)+arctan(1+x)=arctan(1/8)

arctan (1 - x) + arctan (1 + x) = arctan (\frac{1}{8})

x = 4, x = - 4

Solution steps

arctan (1 - x) + arctan (1 + x) = arctan (\frac{1}{8})

Rewrite using trig identities

arctan (\frac{1 - x + 1 + x}{1 - ( 1 - x ) ( 1 + x )}) = arctan (\frac{1}{8})

Apply trig inverse properties

\frac{1 - x + 1 + x}{1 - ( 1 - x ) ( 1 + x )} = \frac{1}{8}

Solve

\frac{1 - x + 1 + x}{1 - ( 1 - x ) ( 1 + x )} = \frac{1}{8} : x = 4, x = - 4

x = 4, x = - 4

Verify solutions by plugging them into the original equation

x = 4, x = - 4

5 sin (4 x) = 2

2 cos^{2} (x) - 3 \cdot sin^{2} (x) - 2 = 0

x, lo g_{10} (y) = arctan (x) + c

2 sin (x) = \frac{( 4 sin ( x ) - cos ( x ) )}{2}

cos (x + 60) \cdot cos (x - 60) = \frac{1}{2}

What is the general solution for arctan(1-x)+arctan(1+x)=arctan(1/8) ?
The general solution for arctan(1-x)+arctan(1+x)=arctan(1/8) is x=4,x=-4