What is the general solution for 2cos^2(x)-sqrt(3)*sin^2(x)-2=0 ?

The general solution for 2cos^2(x)-sqrt(3)*sin^2(x)-2=0 is x=2pin,x=pi+2pin

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2cos^2(x)-sqrt(3)*sin^2(x)-2=0

2 cos^{2} (x) - 3 \cdot sin^{2} (x) - 2 = 0

x = 2 πn, x = π + 2 πn

Solution steps

2 cos^{2} (x) - 3 sin^{2} (x) - 2 = 0

Rewrite using trig identities

- 2 sin^{2} (x) - sin^{2} (x) 3 = 0

Solve by substitution

sin (x) = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn

x, lo g_{10} (y) = arctan (x) + c

2 sin (x) = \frac{( 4 sin ( x ) - cos ( x ) )}{2}

cos (x + 60) \cdot cos (x - 60) = \frac{1}{2}

\frac{cos ( 2 x + 9 )}{3} = \frac{1}{2}

sin^{6} (x) - cos^{6} (x) = 0

What is the general solution for 2cos^2(x)-sqrt(3)*sin^2(x)-2=0 ?
The general solution for 2cos^2(x)-sqrt(3)*sin^2(x)-2=0 is x=2pin,x=pi+2pin