What is the general solution for (cos(2x+9))/3 = 1/2 ?

The general solution for (cos(2x+9))/3 = 1/2 is No Solution for x\in\mathbb{R}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(cos(2x+9))/3 = 1/2

\frac{cos ( 2 x + 9 )}{3} = \frac{1}{2}

No Solution for x \in R

Solution steps

\frac{cos ( 2 x + 9 )}{3} = \frac{1}{2}

Multiply both sides by

3

\frac{cos ( 2 x + 9 )}{3} = \frac{1}{2}

Multiply both sides by

3

\frac{3 cos ( 2 x + 9 )}{3} = \frac{1 \cdot 3}{2}

Simplify

\frac{3 cos ( 2 x + 9 )}{3} = \frac{1 \cdot 3}{2}

Simplify

\frac{3 cos ( 2 x + 9 )}{3} : cos (2 x + 9)

\frac{3 cos ( 2 x + 9 )}{3}

Divide the numbers:

\frac{3}{3} = 1

= cos (2 x + 9)

Simplify

\frac{1 \cdot 3}{2} : \frac{3}{2}

\frac{1 \cdot 3}{2}

Multiply the numbers:

1 \cdot 3 = 3

= \frac{3}{2}

cos (2 x + 9) = \frac{3}{2}

cos (2 x + 9) = \frac{3}{2}

cos (2 x + 9) = \frac{3}{2}

- 1 \leq cos (x) \leq 1

No Solution for x \in R

What is the general solution for (cos(2x+9))/3 = 1/2 ?
The general solution for (cos(2x+9))/3 = 1/2 is No Solution for x\in\mathbb{R}