What is the general solution for solvefor x,2sin((pi(x-2))/6)=1 ?

The general solution for solvefor x,2sin((pi(x-2))/6)=1 is x=12n+3,x=12n+7

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solvefor x,2sin((pi(x-2))/6)=1

solve for

x, 2 sin (\frac{π ( x - 2 )}{6}) = 1

x = 12 n + 3, x = 12 n + 7

Solution steps

2 sin (\frac{π ( x - 2 )}{6}) = 1

Divide both sides by

2

sin (\frac{π ( x - 2 )}{6}) = \frac{1}{2}

General solutions for

sin (\frac{π ( x - 2 )}{6}) = \frac{1}{2}

\frac{π ( x - 2 )}{6} = \frac{π}{6} + 2 πn, \frac{π ( x - 2 )}{6} = \frac{5 π}{6} + 2 πn

Solve

\frac{π ( x - 2 )}{6} = \frac{π}{6} + 2 πn : x = 12 n + 3

Solve

\frac{π ( x - 2 )}{6} = \frac{5 π}{6} + 2 πn : x = 12 n + 7

x = 12 n + 3, x = 12 n + 7

(1 - sin (x)) (1 - sin (x)) = cos^{2} (x)

2 cos (x) = cos^{2} (x) - 1

2 sin (v) csc (v) - csc (v) = 4 sin (v) - 2

2 cos (2 x) = 4 cos (x)

\frac{sin ( 4 2 ^{\circ} )}{22} = \frac{sin ( B )}{12}

What is the general solution for solvefor x,2sin((pi(x-2))/6)=1 ?
The general solution for solvefor x,2sin((pi(x-2))/6)=1 is x=12n+3,x=12n+7