{
"query": {
"display": "$$2\\cos\\left(x\\right)=\\cos^{2}\\left(x\\right)-1$$",
"symbolab_question": "EQUATION#2\\cos(x)=\\cos^{2}(x)-1"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=1.99787…+2πn,x=-1.99787…+2πn",
"degrees": "x=114.46980…^{\\circ }+360^{\\circ }n,x=-114.46980…^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$2\\cos\\left(x\\right)=\\cos^{2}\\left(x\\right)-1{\\quad:\\quad}x=1.99787…+2πn,\\:x=-1.99787…+2πn$$",
"input": "2\\cos\\left(x\\right)=\\cos^{2}\\left(x\\right)-1",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "2\\cos\\left(x\\right)=\\cos^{2}\\left(x\\right)-1",
"result": "\\cos\\left(x\\right)=1+\\sqrt{2},\\:\\cos\\left(x\\right)=1-\\sqrt{2}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(x\\right)=u$$",
"result": "2u=u^{2}-1"
},
{
"type": "interim",
"title": "$$2u=u^{2}-1{\\quad:\\quad}u=1+\\sqrt{2},\\:u=1-\\sqrt{2}$$",
"input": "2u=u^{2}-1",
"steps": [
{
"type": "step",
"primary": "Switch sides",
"result": "u^{2}-1=2u"
},
{
"type": "interim",
"title": "Move $$2u\\:$$to the left side",
"input": "u^{2}-1=2u",
"result": "u^{2}-1-2u=0",
"steps": [
{
"type": "step",
"primary": "Subtract $$2u$$ from both sides",
"result": "u^{2}-1-2u=2u-2u"
},
{
"type": "step",
"primary": "Simplify",
"result": "u^{2}-1-2u=0"
}
],
"meta": {
"interimType": "Move to the Left Title 1Eq",
"gptData": "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"
}
},
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c=0$$",
"result": "u^{2}-2u-1=0"
},
{
"type": "interim",
"title": "Solve with the quadratic formula",
"input": "u^{2}-2u-1=0",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-2\\right)\\pm\\:\\sqrt{\\left(-2\\right)^{2}-4\\cdot\\:1\\cdot\\:\\left(-1\\right)}}{2\\cdot\\:1}",
"steps": [
{
"type": "definition",
"title": "Quadratic Equation Formula:",
"text": "For a quadratic equation of the form $$ax^2+bx+c=0$$ the solutions are <br/>$${\\quad}x_{1,\\:2}=\\frac{-b\\pm\\sqrt{b^2-4ac}}{2a}$$"
},
{
"type": "step",
"primary": "For $${\\quad}a=1,\\:b=-2,\\:c=-1$$",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-2\\right)\\pm\\:\\sqrt{\\left(-2\\right)^{2}-4\\cdot\\:1\\cdot\\:\\left(-1\\right)}}{2\\cdot\\:1}"
}
],
"meta": {
"interimType": "Solving The Quadratic Equation With Quadratic Formula Definition 0Eq",
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}
},
{
"type": "interim",
"title": "$$\\sqrt{\\left(-2\\right)^{2}-4\\cdot\\:1\\cdot\\:\\left(-1\\right)}=2\\sqrt{2}$$",
"input": "\\sqrt{\\left(-2\\right)^{2}-4\\cdot\\:1\\cdot\\:\\left(-1\\right)}",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-2\\right)\\pm\\:2\\sqrt{2}}{2\\cdot\\:1}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\sqrt{\\left(-2\\right)^{2}+4\\cdot\\:1\\cdot\\:1}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(-a\\right)^{n}=a^{n},\\:$$if $$n$$ is even",
"secondary": [
"$$\\left(-2\\right)^{2}=2^{2}$$"
],
"result": "=\\sqrt{2^{2}+4\\cdot\\:1\\cdot\\:1}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$4\\cdot\\:1\\cdot\\:1=4$$",
"result": "=\\sqrt{2^{2}+4}"
},
{
"type": "step",
"primary": "$$2^{2}=4$$",
"result": "=\\sqrt{4+4}"
},
{
"type": "step",
"primary": "Add the numbers: $$4+4=8$$",
"result": "=\\sqrt{8}"
},
{
"type": "interim",
"title": "Prime factorization of $$8:{\\quad}2^{3}$$",
"input": "8",
"result": "=\\sqrt{2^{3}}",
"steps": [
{
"type": "step",
"primary": "$$8\\:$$divides by $$2\\quad\\:8=4\\cdot\\:2$$",
"result": "=2\\cdot\\:4"
},
{
"type": "step",
"primary": "$$4\\:$$divides by $$2\\quad\\:4=2\\cdot\\:2$$",
"result": "=2\\cdot\\:2\\cdot\\:2"
},
{
"type": "step",
"primary": "$$2$$ is a prime number, therefore no further factorization is possible",
"result": "=2\\cdot\\:2\\cdot\\:2"
},
{
"type": "step",
"result": "=2^{3}"
}
],
"meta": {
"solvingClass": "Composite Integer",
"interimType": "Prime Fac 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xyoU2cWyPLDgE1QLLHeauuc3PHQdChPJ2JhfqHT+ZU0OMrfn8NOj0LUzuzje6xTyxRtXnBik8vDPXVw+nKWp28DI/y9DKGIPglJ+qMi9xDu2KE1OovxZAaXg7BtrFPk4UcCzRnGgMN6CYRfod7Mq0dp1RcgsS082tQWmOBW6FvhEw"
}
},
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^b\\cdot\\:a^c$$",
"result": "=\\sqrt{2^{2}\\cdot\\:2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{ab}=\\sqrt[n]{a}\\sqrt[n]{b}$$",
"result": "=\\sqrt{2}\\sqrt{2^{2}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{2^{2}}=2$$"
],
"result": "=2\\sqrt{2}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7z3fhNomdwT8bNJhnZYfuTnGW/jTwUrqHAcqr1cHDsBC+r46Eolb4yfb3qibo0qjOCUCWbkwGOY7PqKo3U/JLJVmgCQUJbEmB6Cz9dIGB/Jujeh7+jKEzLb7VNCEMF3Z/sqxBQpByw1rOs2gJDdV//L292pD5hySoUKIRHggU0KNwuhBMtn2r3wONHUGucsPbJLd1ohke2Wgml78++2zI0g=="
}
},
{
"type": "step",
"primary": "Separate the solutions",
"result": "{u}_{1}=\\frac{-\\left(-2\\right)+2\\sqrt{2}}{2\\cdot\\:1},\\:{u}_{2}=\\frac{-\\left(-2\\right)-2\\sqrt{2}}{2\\cdot\\:1}"
},
{
"type": "interim",
"title": "$$u=\\frac{-\\left(-2\\right)+2\\sqrt{2}}{2\\cdot\\:1}:{\\quad}1+\\sqrt{2}$$",
"input": "\\frac{-\\left(-2\\right)+2\\sqrt{2}}{2\\cdot\\:1}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{2+2\\sqrt{2}}{2\\cdot\\:1}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:1=2$$",
"result": "=\\frac{2+2\\sqrt{2}}{2}"
},
{
"type": "interim",
"title": "Factor $$2+2\\sqrt{2}:{\\quad}2\\left(1+\\sqrt{2}\\right)$$",
"input": "2+2\\sqrt{2}",
"result": "=\\frac{2\\left(1+\\sqrt{2}\\right)}{2}",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "=2\\cdot\\:1+2\\sqrt{2}"
},
{
"type": "step",
"primary": "Factor out common term $$2$$",
"result": "=2\\left(1+\\sqrt{2}\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=1+\\sqrt{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7Fv9gVNWyI/X8TvzzSZV8n9BT7cqoSAntC7uTSLRIMJq2yYtEqeT7UjI2zAoMd7PXcJChiVhDxT5N/LHSTLMjyB2rzZnucNvBU5dymMSHT2JBYjcLsCD0zopRg7yXiHFAz1ZIwC6YFMYnp61N6d4aXelnqK0S844f1w6EAcTrejRsZSEP36ANCDTv0XrTRe7l"
}
},
{
"type": "interim",
"title": "$$u=\\frac{-\\left(-2\\right)-2\\sqrt{2}}{2\\cdot\\:1}:{\\quad}1-\\sqrt{2}$$",
"input": "\\frac{-\\left(-2\\right)-2\\sqrt{2}}{2\\cdot\\:1}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{2-2\\sqrt{2}}{2\\cdot\\:1}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:1=2$$",
"result": "=\\frac{2-2\\sqrt{2}}{2}"
},
{
"type": "interim",
"title": "Factor $$2-2\\sqrt{2}:{\\quad}2\\left(1-\\sqrt{2}\\right)$$",
"input": "2-2\\sqrt{2}",
"result": "=\\frac{2\\left(1-\\sqrt{2}\\right)}{2}",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "=2\\cdot\\:1-2\\sqrt{2}"
},
{
"type": "step",
"primary": "Factor out common term $$2$$",
"result": "=2\\left(1-\\sqrt{2}\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"primary": "Divide the numbers: $$\\frac{2}{2}=1$$",
"result": "=1-\\sqrt{2}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7yzZ+Rg5UPtRAM2q6UZuzBtBT7cqoSAntC7uTSLRIMJq2yYtEqeT7UjI2zAoMd7PXcJChiVhDxT5N/LHSTLMjyIcYUBmC3eatQPHmRkJsiutBYjcLsCD0zopRg7yXiHFAHY/HyZjN1C2qZGgDt8Y8hulnqK0S844f1w6EAcTrejRsZSEP36ANCDTv0XrTRe7l"
}
},
{
"type": "step",
"primary": "The solutions to the quadratic equation are:",
"result": "u=1+\\sqrt{2},\\:u=1-\\sqrt{2}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(x\\right)$$",
"result": "\\cos\\left(x\\right)=1+\\sqrt{2},\\:\\cos\\left(x\\right)=1-\\sqrt{2}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(x\\right)=1+\\sqrt{2}{\\quad:\\quad}$$No Solution",
"input": "\\cos\\left(x\\right)=1+\\sqrt{2}",
"steps": [
{
"type": "step",
"primary": "$$-1\\le\\cos\\left(x\\right)\\le1$$",
"result": "\\mathrm{No\\:Solution}"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(x\\right)=1-\\sqrt{2}{\\quad:\\quad}x=\\arccos\\left(1-\\sqrt{2}\\right)+2πn,\\:x=-\\arccos\\left(1-\\sqrt{2}\\right)+2πn$$",
"input": "\\cos\\left(x\\right)=1-\\sqrt{2}",
"steps": [
{
"type": "interim",
"title": "Apply trig inverse properties",
"input": "\\cos\\left(x\\right)=1-\\sqrt{2}",
"result": "x=\\arccos\\left(1-\\sqrt{2}\\right)+2πn,\\:x=-\\arccos\\left(1-\\sqrt{2}\\right)+2πn",
"steps": [
{
"type": "step",
"primary": "General solutions for $$\\cos\\left(x\\right)=1-\\sqrt{2}$$",
"secondary": [
"$$\\cos\\left(x\\right)=-a\\quad\\Rightarrow\\quad\\:x=\\arccos\\left(-a\\right)+2πn,\\:\\quad\\:x=-\\arccos\\left(-a\\right)+2πn$$"
],
"result": "x=\\arccos\\left(1-\\sqrt{2}\\right)+2πn,\\:x=-\\arccos\\left(1-\\sqrt{2}\\right)+2πn"
}
],
"meta": {
"interimType": "Trig Apply Inverse Props 0Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "x=\\arccos\\left(1-\\sqrt{2}\\right)+2πn,\\:x=-\\arccos\\left(1-\\sqrt{2}\\right)+2πn"
},
{
"type": "step",
"primary": "Show solutions in decimal form",
"result": "x=1.99787…+2πn,\\:x=-1.99787…+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "2\\cos(x)-\\cos^{2}(x)+1"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Switch sides
Move to the left side
Subtract from both sides
Simplify
Write in the standard form
Solve with the quadratic formula
Quadratic Equation Formula:
For
Apply rule
Apply exponent rule: if is even
Multiply the numbers:
Add the numbers:
Prime factorization of
divides by
divides by
is a prime number, therefore no further factorization is possible
Apply exponent rule:
Apply radical rule:
Apply radical rule:
Separate the solutions
Apply rule
Multiply the numbers:
Factor
Rewrite as
Factor out common term
Divide the numbers:
Apply rule
Multiply the numbers:
Factor
Rewrite as
Factor out common term
Divide the numbers:
The solutions to the quadratic equation are:
Substitute back
No Solution
Apply trig inverse properties
General solutions for
Combine all the solutions
Show solutions in decimal form
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is the general solution for 2cos(x)=cos^2(x)-1 ?
The general solution for 2cos(x)=cos^2(x)-1 is x=1.99787…+2pin,x=-1.99787…+2pin