What is the general solution for 2sin(x)=-1,-pi<= x<= pi ?

The general solution for 2sin(x)=-1,-pi<= x<= pi is x=-(5pi)/6 ,x=-pi/6

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2sin(x)=-1,-pi<= x<= pi

2 sin (x) = - 1, - π \leq x \leq π

x = - \frac{5 π}{6}, x = - \frac{π}{6}

Solution steps

2 sin (x) = - 1, - π \leq x \leq π

Divide both sides by

2

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solutions for the range

- π \leq x \leq π

x = - \frac{5 π}{6}, x = - \frac{π}{6}

cot (- \frac{π}{5}) - sec (x) = 1.5

\frac{1}{cos ^{2} ( x )} + (\frac{1}{2 cos ( x )}) = 0

3 sin (x) + cos (x) = 2

cos (α) = \frac{1 + \frac{1}{5}}{2}

(tan (x)) (sin^{2} (x) - a) (sec (x) - a) = 0, 0 < a < 1

What is the general solution for 2sin(x)=-1,-pi<= x<= pi ?
The general solution for 2sin(x)=-1,-pi<= x<= pi is x=-(5pi)/6 ,x=-pi/6