What is the general solution for 1/(cos^2(x))+(1/(2cos(x)))=0 ?

The general solution for 1/(cos^2(x))+(1/(2cos(x)))=0 is No Solution for x\in\mathbb{R}

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1/(cos^2(x))+(1/(2cos(x)))=0

\frac{1}{cos ^{2} ( x )} + (\frac{1}{2 cos ( x )}) = 0

No Solution for x \in R

Solution steps

\frac{1}{cos ^{2} ( x )} + (\frac{1}{2 cos ( x )}) = 0

Solve by substitution

cos (x) = - 2

cos (x) = - 2 :

No Solution

Combine all the solutions

No Solution for x \in R

3 sin (x) + cos (x) = 2

cos (α) = \frac{1 + \frac{1}{5}}{2}

(tan (x)) (sin^{2} (x) - a) (sec (x) - a) = 0, 0 < a < 1

sin (\frac{π}{2} (x + 1)) = \frac{2}{5}

sin (\cdot + \frac{π}{2}) = cos (x)

What is the general solution for 1/(cos^2(x))+(1/(2cos(x)))=0 ?
The general solution for 1/(cos^2(x))+(1/(2cos(x)))=0 is No Solution for x\in\mathbb{R}