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Popular Trigonometry >

sin(pi/2 (x+1))= 2/5

  • Pre Algebra
  • Algebra
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Solution

sin(2π​(x+1))=52​

Solution

x=π2⋅0.41151…​+4n−1,x=4n+1−π2⋅0.41151…​
+1
Degrees
x=−42.28544…∘+229.18311…∘n,x=42.28544…∘+229.18311…∘n
Solution steps
sin(2π​(x+1))=52​
Apply trig inverse properties
sin(2π​(x+1))=52​
General solutions for sin(2π​(x+1))=52​sin(x)=a⇒x=arcsin(a)+2πn,x=π−arcsin(a)+2πn2π​(x+1)=arcsin(52​)+2πn,2π​(x+1)=π−arcsin(52​)+2πn
2π​(x+1)=arcsin(52​)+2πn,2π​(x+1)=π−arcsin(52​)+2πn
Solve 2π​(x+1)=arcsin(52​)+2πn:x=π2arcsin(52​)​+4n−1
2π​(x+1)=arcsin(52​)+2πn
Multiply both sides by 2
2π​(x+1)=arcsin(52​)+2πn
Multiply both sides by 22⋅2π​(x+1)=2arcsin(52​)+2⋅2πn
Simplify
2⋅2π​(x+1)=2arcsin(52​)+2⋅2πn
Simplify 2⋅2π​(x+1):π(x+1)
2⋅2π​(x+1)
Multiply fractions: a⋅cb​=ca⋅b​=22π​(x+1)
Cancel the common factor: 2=(x+1)π
Simplify 2arcsin(52​)+2⋅2πn:2arcsin(52​)+4πn
2arcsin(52​)+2⋅2πn
Multiply the numbers: 2⋅2=4=2arcsin(52​)+4πn
π(x+1)=2arcsin(52​)+4πn
π(x+1)=2arcsin(52​)+4πn
π(x+1)=2arcsin(52​)+4πn
Divide both sides by π
π(x+1)=2arcsin(52​)+4πn
Divide both sides by πππ(x+1)​=π2arcsin(52​)​+π4πn​
Simplifyx+1=π2arcsin(52​)​+4n
x+1=π2arcsin(52​)​+4n
Move 1to the right side
x+1=π2arcsin(52​)​+4n
Subtract 1 from both sidesx+1−1=π2arcsin(52​)​+4n−1
Simplifyx=π2arcsin(52​)​+4n−1
x=π2arcsin(52​)​+4n−1
Solve 2π​(x+1)=π−arcsin(52​)+2πn:x=4n+1−π2arcsin(52​)​
2π​(x+1)=π−arcsin(52​)+2πn
Multiply both sides by 2
2π​(x+1)=π−arcsin(52​)+2πn
Multiply both sides by 22⋅2π​(x+1)=2π−2arcsin(52​)+2⋅2πn
Simplify
2⋅2π​(x+1)=2π−2arcsin(52​)+2⋅2πn
Simplify 2⋅2π​(x+1):π(x+1)
2⋅2π​(x+1)
Multiply fractions: a⋅cb​=ca⋅b​=22π​(x+1)
Cancel the common factor: 2=(x+1)π
Simplify 2π−2arcsin(52​)+2⋅2πn:2π−2arcsin(52​)+4πn
2π−2arcsin(52​)+2⋅2πn
Multiply the numbers: 2⋅2=4=2π−2arcsin(52​)+4πn
π(x+1)=2π−2arcsin(52​)+4πn
π(x+1)=2π−2arcsin(52​)+4πn
π(x+1)=2π−2arcsin(52​)+4πn
Divide both sides by π
π(x+1)=2π−2arcsin(52​)+4πn
Divide both sides by πππ(x+1)​=π2π​−π2arcsin(52​)​+π4πn​
Simplify
ππ(x+1)​=π2π​−π2arcsin(52​)​+π4πn​
Simplify ππ(x+1)​:x+1
ππ(x+1)​
Cancel the common factor: π=x+1
Simplify π2π​−π2arcsin(52​)​+π4πn​:2−π2arcsin(52​)​+4n
π2π​−π2arcsin(52​)​+π4πn​
Cancel π2π​:2
π2π​
Cancel the common factor: π=2
=2−π2arcsin(52​)​+π4πn​
Cancel π4πn​:4n
π4πn​
Cancel the common factor: π=4n
=2−π2arcsin(52​)​+4n
x+1=2−π2arcsin(52​)​+4n
x+1=2−π2arcsin(52​)​+4n
x+1=2−π2arcsin(52​)​+4n
Move 1to the right side
x+1=2−π2arcsin(52​)​+4n
Subtract 1 from both sidesx+1−1=2−π2arcsin(52​)​+4n−1
Simplify
x+1−1=2−π2arcsin(52​)​+4n−1
Simplify x+1−1:x
x+1−1
Add similar elements: 1−1=0
=x
Simplify 2−π2arcsin(52​)​+4n−1:4n+1−π2arcsin(52​)​
2−π2arcsin(52​)​+4n−1
Subtract the numbers: 2−1=1=4n+1−π2arcsin(52​)​
x=4n+1−π2arcsin(52​)​
x=4n+1−π2arcsin(52​)​
x=4n+1−π2arcsin(52​)​
x=π2arcsin(52​)​+4n−1,x=4n+1−π2arcsin(52​)​
Show solutions in decimal formx=π2⋅0.41151…​+4n−1,x=4n+1−π2⋅0.41151…​

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Popular Examples

sin(*+pi/2)=cos(x)sin(θ)=(0.000069)2(500*10^{-9})(2sin^2(x)-1)(tan(x)-1)=0(csc(x)+2)(csc(x)-sqrt(2))=0,0<= x<= 2picos(x)=55

Frequently Asked Questions (FAQ)

  • What is the general solution for sin(pi/2 (x+1))= 2/5 ?

    The general solution for sin(pi/2 (x+1))= 2/5 is x=(2*0.41151…)/pi+4n-1,x=4n+1-(2*0.41151…)/pi
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