What is the general solution for cos(α)=sqrt((1+1/5)/2) ?

The general solution for cos(α)=sqrt((1+1/5)/2) is α=0.68471…+2pin,α=2pi-0.68471…+2pin

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cos(α)=sqrt((1+1/5)/2)

cos (α) = \frac{1 + \frac{1}{5}}{2}

α = 0.68471 \dots + 2 πn, α = 2 π - 0.68471 \dots + 2 πn

Solution steps

cos (α) = \frac{1 + \frac{1}{5}}{2}

\frac{1 + \frac{1}{5}}{2} = \frac{3}{5}

cos (α) = \frac{3}{5}

Apply trig inverse properties

α = arccos (\frac{3}{5}) + 2 πn, α = 2 π - arccos (\frac{3}{5}) + 2 πn

Show solutions in decimal form

α = 0.68471 \dots + 2 πn, α = 2 π - 0.68471 \dots + 2 πn

(tan (x)) (sin^{2} (x) - a) (sec (x) - a) = 0, 0 < a < 1

sin (\frac{π}{2} (x + 1)) = \frac{2}{5}

sin (\cdot + \frac{π}{2}) = cos (x)

sin (θ) = (0.000069) 2 (500 \cdot 1 0^{- 9})

(2 sin^{2} (x) - 1) (tan (x) - 1) = 0

What is the general solution for cos(α)=sqrt((1+1/5)/2) ?
The general solution for cos(α)=sqrt((1+1/5)/2) is α=0.68471…+2pin,α=2pi-0.68471…+2pin