What is the general solution for cos(x)=-3/5 ,pi<x<(3pi)/2 ,sin(x/2) ?

The general solution for cos(x)=-3/5 ,pi<x<(3pi)/2 ,sin(x/2) is x=-2.21429…+2pi

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cos(x)=-3/5 ,pi<x<(3pi)/2 ,sin(x/2)

cos (x) = - \frac{3}{5}, π < x < \frac{3 π}{2}, sin (\frac{x}{2})

x = - 2.21429 \dots + 2 π

Solution steps

cos (x) = - \frac{3}{5}, π < x < \frac{3 π}{2}, sin (\frac{x}{2})

Apply trig inverse properties

x = arccos (- \frac{3}{5}) + 2 πn, x = - arccos (- \frac{3}{5}) + 2 πn

Solutions for the range

π < x < \frac{3 π}{2}

x = - arccos (- \frac{3}{5}) + 2 π

Show solutions in decimal form

x = - 2.21429 \dots + 2 π

3 0^{\circ} = arccos (\frac{6}{x ( 3 )})

sin (θ) = 0.18421

\frac{6}{3 tan ( θ ) + 1} = 5

cos (x) = 2 - 3 sin (x)

tan (\frac{x}{2}) = 1, 5

What is the general solution for cos(x)=-3/5 ,pi<x<(3pi)/2 ,sin(x/2) ?
The general solution for cos(x)=-3/5 ,pi<x<(3pi)/2 ,sin(x/2) is x=-2.21429…+2pi