What is the general solution for 30=arccos(6/(x(3))) ?

The general solution for 30=arccos(6/(x(3))) is x= 4/(sqrt(3))

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30=arccos(6/(x(3)))

3 0^{\circ} = arccos (\frac{6}{x ( 3 )})

x = \frac{4}{3}

Solution steps

3 0^{\circ} = arccos (\frac{6}{x ( 3 )})

Switch sides

arccos (\frac{6}{x \cdot 3}) = 3 0^{\circ}

Apply trig inverse properties

\frac{6}{x \cdot 3} = \frac{3}{2}

Solve

\frac{6}{x \cdot 3} = \frac{3}{2} : x = \frac{4}{3}

x = \frac{4}{3}

sin (θ) = 0.18421

\frac{6}{3 tan ( θ ) + 1} = 5

cos (x) = 2 - 3 sin (x)

tan (\frac{x}{2}) = 1, 5

2 cos^{2} (x) - 1 - cos (x) = 0, 0 \leq x \leq 2 π

What is the general solution for 30=arccos(6/(x(3))) ?
The general solution for 30=arccos(6/(x(3))) is x= 4/(sqrt(3))