What is the general solution for 2sin(A)-1=0 ?

The general solution for 2sin(A)-1=0 is A= pi/6+2pin,A=(5pi)/6+2pin

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2sin(A)-1=0

2 sin (A) - 1 = 0

A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

Solution steps

2 sin (A) - 1 = 0

Move

1

to the right side

2 sin (A) = 1

Divide both sides by

2

sin (A) = \frac{1}{2}

General solutions for

sin (A) = \frac{1}{2}

A = \frac{π}{6} + 2 πn, A = \frac{5 π}{6} + 2 πn

cos (5 θ) = cos (3 θ)

cos (x 1) - cos (x 2) = cos (x 1 - x 2)

8 \cdot sin^{2} (2 x) - 2 \cdot sin (2 x) - 1 = 0

4 - 2 cos (2 x) = 0

x, 2 cos^{2} (x) + sin (x) = 1

What is the general solution for 2sin(A)-1=0 ?
The general solution for 2sin(A)-1=0 is A= pi/6+2pin,A=(5pi)/6+2pin