What is the general solution for solvefor x,-4cos(x)=-sin^2(x)+4 ?

The general solution for solvefor x,-4cos(x)=-sin^2(x)+4 is x=pi+2pin

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solvefor x,-4cos(x)=-sin^2(x)+4

solve for

x, - 4 cos (x) = - sin^{2} (x) + 4

x = π + 2 πn

Solution steps

- 4 cos (x) = - sin^{2} (x) + 4

Subtract

- sin^{2} (x) + 4

from both sides

- 4 cos (x) + sin^{2} (x) - 4 = 0

Rewrite using trig identities

- 3 - cos^{2} (x) - 4 cos (x) = 0

Solve by substitution

cos (x) = - 3, cos (x) = - 1

cos (x) = - 3 :

No Solution

cos (x) = - 1 : x = π + 2 πn

Combine all the solutions

x = π + 2 πn

5 cos (c) + 23 = 0

cos (2 θ) = - \frac{28}{53}

cos (θ) = \frac{( 1 )}{( 2 )}

csc (x) (cos^{2} (x) + 2) = 0

cos (x - \frac{3}{2} π) = - \frac{2}{2}

What is the general solution for solvefor x,-4cos(x)=-sin^2(x)+4 ?
The general solution for solvefor x,-4cos(x)=-sin^2(x)+4 is x=pi+2pin