What is the general solution for cos(2θ)=-28/53 ?

The general solution for cos(2θ)=-28/53 is θ=(2.12739…)/2+pin,θ=-(2.12739…)/2+pin

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cos(2θ)=-28/53

cos (2 θ) = - \frac{28}{53}

θ = \frac{2.12739 \dots}{2} + πn, θ = - \frac{2.12739 \dots}{2} + πn

Solution steps

cos (2 θ) = - \frac{28}{53}

Apply trig inverse properties

2 θ = arccos (- \frac{28}{53}) + 2 πn, 2 θ = - arccos (- \frac{28}{53}) + 2 πn

Solve

2 θ = arccos (- \frac{28}{53}) + 2 πn : θ = \frac{arccos ( - \frac{28}{53} )}{2} + πn

Solve

2 θ = - arccos (- \frac{28}{53}) + 2 πn : θ = - \frac{arccos ( - \frac{28}{53} )}{2} + πn

θ = \frac{arccos ( - \frac{28}{53} )}{2} + πn, θ = - \frac{arccos ( - \frac{28}{53} )}{2} + πn

Show solutions in decimal form

θ = \frac{2.12739 \dots}{2} + πn, θ = - \frac{2.12739 \dots}{2} + πn

cos (θ) = \frac{( 1 )}{( 2 )}

csc (x) (cos^{2} (x) + 2) = 0

cos (x - \frac{3}{2} π) = - \frac{2}{2}

tan (2 θ) = 0.5

146 = (8 - cos (θ))^{2} + (- 9 - sin (θ))^{2}

What is the general solution for cos(2θ)=-28/53 ?
The general solution for cos(2θ)=-28/53 is θ=(2.12739…)/2+pin,θ=-(2.12739…)/2+pin