{
"query": {
"display": "$$6\\cos\\left(x\\right)=2+2\\cos\\left(x\\right)$$",
"symbolab_question": "EQUATION#6\\cos(x)=2+2\\cos(x)"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=\\frac{π}{3}+2πn,x=\\frac{5π}{3}+2πn",
"degrees": "x=60^{\\circ }+360^{\\circ }n,x=300^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$6\\cos\\left(x\\right)=2+2\\cos\\left(x\\right){\\quad:\\quad}x=\\frac{π}{3}+2πn,\\:x=\\frac{5π}{3}+2πn$$",
"input": "6\\cos\\left(x\\right)=2+2\\cos\\left(x\\right)",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "6\\cos\\left(x\\right)=2+2\\cos\\left(x\\right)",
"result": "\\cos\\left(x\\right)=\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(x\\right)=u$$",
"result": "6u=2+2u"
},
{
"type": "interim",
"title": "$$6u=2+2u{\\quad:\\quad}u=\\frac{1}{2}$$",
"input": "6u=2+2u",
"steps": [
{
"type": "interim",
"title": "Move $$2u\\:$$to the left side",
"input": "6u=2+2u",
"result": "4u=2",
"steps": [
{
"type": "step",
"primary": "Subtract $$2u$$ from both sides",
"result": "6u-2u=2+2u-2u"
},
{
"type": "step",
"primary": "Simplify",
"result": "4u=2"
}
],
"meta": {
"interimType": "Move to the Left Title 1Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "Divide both sides by $$4$$",
"input": "4u=2",
"result": "u=\\frac{1}{2}",
"steps": [
{
"type": "step",
"primary": "Divide both sides by $$4$$",
"result": "\\frac{4u}{4}=\\frac{2}{4}"
},
{
"type": "step",
"primary": "Simplify",
"result": "u=\\frac{1}{2}"
}
],
"meta": {
"interimType": "Divide Both Sides Specific 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(x\\right)$$",
"result": "\\cos\\left(x\\right)=\\frac{1}{2}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(x\\right)=\\frac{1}{2}{\\quad:\\quad}x=\\frac{π}{3}+2πn,\\:x=\\frac{5π}{3}+2πn$$",
"input": "\\cos\\left(x\\right)=\\frac{1}{2}",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\cos\\left(x\\right)=\\frac{1}{2}$$",
"result": "x=\\frac{π}{3}+2πn,\\:x=\\frac{5π}{3}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\cos\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\cos(x)&x&\\cos(x)\\\\\\hline 0&1&π&-1\\\\\\hline \\frac{π}{6}&\\frac{\\sqrt{3}}{2}&\\frac{7π}{6}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{1}{2}&\\frac{4π}{3}&-\\frac{1}{2}\\\\\\hline \\frac{π}{2}&0&\\frac{3π}{2}&0\\\\\\hline \\frac{2π}{3}&-\\frac{1}{2}&\\frac{5π}{3}&\\frac{1}{2}\\\\\\hline \\frac{3π}{4}&-\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&-\\frac{\\sqrt{3}}{2}&\\frac{11π}{6}&\\frac{\\sqrt{3}}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "x=\\frac{π}{3}+2πn,\\:x=\\frac{5π}{3}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions cos 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "x=\\frac{π}{3}+2πn,\\:x=\\frac{5π}{3}+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "6\\cos(x)-2-2\\cos(x)"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Move to the left side
Subtract from both sides
Simplify
Divide both sides by
Divide both sides by
Simplify
Substitute back
General solutions for
periodicity table with cycle:
Combine all the solutions
Graph
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Frequently Asked Questions (FAQ)
What is the general solution for 6cos(x)=2+2cos(x) ?
The general solution for 6cos(x)=2+2cos(x) is x= pi/3+2pin,x=(5pi)/3+2pin