What is the general solution for 4sin(x)+2sqrt(2)=0 ?

The general solution for 4sin(x)+2sqrt(2)=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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4sin(x)+2sqrt(2)=0

4 sin (x) + 22 = 0

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Degrees

x = 22 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

Solution steps

4 sin (x) + 22 = 0

Move

22

to the right side

4 sin (x) + 22 = 0

Subtract

22

from both sides

4 sin (x) + 22 - 22 = 0 - 22

Simplify

4 sin (x) = - 22

4 sin (x) = - 22

Divide both sides by

4

4 sin (x) = - 22

Divide both sides by

4

\frac{4 sin ( x )}{4} = \frac{- 2 2}{4}

Simplify

\frac{4 sin ( x )}{4} = \frac{- 2 2}{4}

Simplify

\frac{4 sin ( x )}{4} : sin (x)

\frac{4 sin ( x )}{4}

Divide the numbers:

\frac{4}{4} = 1

= sin (x)

Simplify

\frac{- 2 2}{4} : - \frac{2}{2}

\frac{- 2 2}{4}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{2 2}{4}

Cancel the common factor:

2

= - \frac{2}{2}

sin (x) = - \frac{2}{2}

sin (x) = - \frac{2}{2}

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sin (4 x) + sin (2 x) = 0, 0^{\circ} \leq x \leq 18 0^{\circ}

\frac{3 tan ( x )}{sec ( x )} - cos (x) = 0

2 cos (2 x) = 2

sec^{2} (θ) - 2 tan (θ) = 0

sin (2 x) - cos (2 x) = 2

What is the general solution for 4sin(x)+2sqrt(2)=0 ?
The general solution for 4sin(x)+2sqrt(2)=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin