ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある三角関数 >

2sin(2x)=3tan(x)

解

2 sin (2 x) = 3 tan (x)

解

x = 2 πn, x = π + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

+1

度

x = 0^{\circ} + 36 0^{\circ} n, x = 18 0^{\circ} + 36 0^{\circ} n, x = 15 0^{\circ} + 36 0^{\circ} n, x = 21 0^{\circ} + 36 0^{\circ} n, x = 3 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

解答ステップ

2 sin (2 x) = 3 tan (x)

両辺から

3 tan (x)

を引く

2 sin (2 x) - 3 tan (x) = 0

サイン, コサインで表わす

2 sin (2 x) - 3 tan (x)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= 2 sin (2 x) - 3 \cdot \frac{sin ( x )}{cos ( x )}

簡素化

2 sin (2 x) - 3 \cdot \frac{sin ( x )}{cos ( x )} : \frac{2 sin ( 2 x ) cos ( x ) - 3 sin ( x )}{cos ( x )}

2 sin (2 x) - 3 \cdot \frac{sin ( x )}{cos ( x )}

乗じる

3 \cdot \frac{sin ( x )}{cos ( x )} : \frac{3 sin ( x )}{cos ( x )}

3 \cdot \frac{sin ( x )}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) \cdot 3}{cos ( x )}

= 2 sin (2 x) - \frac{3 sin ( x )}{cos ( x )}

元を分数に変換する:

2 sin (2 x) = \frac{2 sin ( 2 x ) cos ( x )}{cos ( x )}

= \frac{2 sin ( 2 x ) cos ( x )}{cos ( x )} - \frac{sin ( x ) \cdot 3}{cos ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 sin ( 2 x ) cos ( x ) - sin ( x ) \cdot 3}{cos ( x )}

= \frac{2 sin ( 2 x ) cos ( x ) - 3 sin ( x )}{cos ( x )}

\frac{- 3 sin ( x ) + 2 cos ( x ) sin ( 2 x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- 3 sin (x) + 2 cos (x) sin (2 x) = 0

三角関数の公式を使用して書き換える

- 3 sin (x) + 2 cos (x) sin (2 x)

2倍角の公式を使用:

sin (2 x) = 2 sin (x) cos (x)

= - 3 sin (x) + 2 cos (x) \cdot 2 sin (x) cos (x)

2 cos (x) \cdot 2 sin (x) cos (x) = 4 cos^{2} (x) sin (x)

2 cos (x) \cdot 2 sin (x) cos (x)

数を乗じる:

2 \cdot 2 = 4

= 4 cos (x) sin (x) cos (x)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

cos (x) cos (x) = cos^{1 + 1} (x)

= 4 sin (x) cos^{1 + 1} (x)

数を足す:

1 + 1 = 2

= 4 sin (x) cos^{2} (x)

= - 3 sin (x) + 4 cos^{2} (x) sin (x)

- 3 sin (x) + 4 cos^{2} (x) sin (x) = 0

因数

- 3 sin (x) + 4 cos^{2} (x) sin (x) : sin (x) (2 cos (x) + 3) (2 cos (x) - 3)

- 3 sin (x) + 4 cos^{2} (x) sin (x)

共通項をくくり出す

sin (x)

= sin (x) (- 3 + 4 cos^{2} (x))

因数

4 cos^{2} (x) - 3 : (2 cos (x) + 3) (2 cos (x) - 3)

4 cos^{2} (x) - 3

4 cos^{2} (x) - 3

を書き換え

(2 cos (x))^{2} - (3)^{2}

4 cos^{2} (x) - 3

4

を書き換え

2^{2}

= 2^{2} cos^{2} (x) - 3

累乗根の規則を適用する:

a = (a)^{2}

3 = (3)^{2}

= 2^{2} cos^{2} (x) - (3)^{2}

指数の規則を適用する:

a^{m} b^{m} = (ab)^{m}

2^{2} cos^{2} (x) = (2 cos (x))^{2}

= (2 cos (x))^{2} - (3)^{2}

= (2 cos (x))^{2} - (3)^{2}

2乗の差の公式を適用する:

x^{2} - y^{2} = (x + y) (x - y)

(2 cos (x))^{2} - (3)^{2} = (2 cos (x) + 3) (2 cos (x) - 3)

= (2 cos (x) + 3) (2 cos (x) - 3)

= sin (x) (2 cos (x) + 3) (2 cos (x) - 3)

sin (x) (2 cos (x) + 3) (2 cos (x) - 3) = 0

各部分を別個に解く

sin (x) = 0 or 2 cos (x) + 3 = 0 or 2 cos (x) - 3 = 0

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 0

以下の一般解

sin (x) = 0

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = 0 + 2 πn, x = π + 2 πn

x = 0 + 2 πn, x = π + 2 πn

解く

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn, x = π + 2 πn

2 cos (x) + 3 = 0 : x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

2 cos (x) + 3 = 0

3

を右側に移動します

2 cos (x) + 3 = 0

両辺から

3

を引く

2 cos (x) + 3 - 3 = 0 - 3

簡素化

2 cos (x) = - 3

2 cos (x) = - 3

以下で両辺を割る

2

2 cos (x) = - 3

以下で両辺を割る

2

\frac{2 cos ( x )}{2} = \frac{- 3}{2}

簡素化

cos (x) = - \frac{3}{2}

cos (x) = - \frac{3}{2}

以下の一般解

cos (x) = - \frac{3}{2}

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn

2 cos (x) - 3 = 0 : x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

2 cos (x) - 3 = 0

3

を右側に移動します

2 cos (x) - 3 = 0

両辺に

3

を足す

2 cos (x) - 3 + 3 = 0 + 3

簡素化

2 cos (x) = 3

2 cos (x) = 3

以下で両辺を割る

2

2 cos (x) = 3

以下で両辺を割る

2

\frac{2 cos ( x )}{2} = \frac{3}{2}

簡素化

cos (x) = \frac{3}{2}

cos (x) = \frac{3}{2}

以下の一般解

cos (x) = \frac{3}{2}

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

すべての解を組み合わせる

x = 2 πn, x = π + 2 πn, x = \frac{5 π}{6} + 2 πn, x = \frac{7 π}{6} + 2 πn, x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

グラフ

人気の例

tan(φ)= 1/(sqrt(3))

tan (φ) = \frac{1}{3}

sin(θ)*csc(18)=1

sin (θ) \cdot csc (1 8^{\circ}) = 1

sin(2x)=cos(x-15)

sin (2 x) = cos (x - 1 5^{\circ})

(1+cos(4x))sin(4x)=cos^2(2x)

(1 + cos (4 x)) sin (4 x) = cos^{2} (2 x)

arcsin(3/5)+arccos(x)=pi

arcsin (\frac{3}{5}) + arccos (x) = π