sin(B)=((240.68*sin(21.16)))/(207.91)

解

sin (B) = \frac{( 240.68 \cdot sin ( 21.1 6 ^{\circ} ) )}{207.91}

B = 0.43109 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.43109 \dots + 36 0^{\circ} n

ラジアン

B = 0.43109 \dots + 2 πn, B = π - 0.43109 \dots + 2 πn

解答ステップ

sin (B) = \frac{( 240.68 sin ( 21.1 6 ^{\circ} ) )}{207.91}

三角関数の逆数プロパティを適用する

sin (B) = \frac{240.68 sin ( 21.1 6 ^{\circ} )}{207.91}

以下の一般解

sin (B) = \frac{240.68 sin ( 21.1 6 ^{\circ} )}{207.91}

sin (x) = a \Rightarrow x = arcsin (a) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (a) + 36 0^{\circ} n

B = arcsin (\frac{240.68 sin ( 21.1 6 ^{\circ} )}{207.91}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{240.68 sin ( 21.1 6 ^{\circ} )}{207.91}) + 36 0^{\circ} n

B = arcsin (\frac{240.68 sin ( 21.1 6 ^{\circ} )}{207.91}) + 36 0^{\circ} n, B = 18 0^{\circ} - arcsin (\frac{240.68 sin ( 21.1 6 ^{\circ} )}{207.91}) + 36 0^{\circ} n

10進法形式で解を証明する

B = 0.43109 \dots + 36 0^{\circ} n, B = 18 0^{\circ} - 0.43109 \dots + 36 0^{\circ} n