What is the general solution for solvefor x,1-cos(x)=0 ?

The general solution for solvefor x,1-cos(x)=0 is x=2pin

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solvefor x,1-cos(x)=0

solve for

x, 1 - cos (x) = 0

x = 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n

Solution steps

1 - cos (x) = 0

Move

1

to the right side

1 - cos (x) = 0

Subtract

1

from both sides

1 - cos (x) - 1 = 0 - 1

Simplify

- cos (x) = - 1

- cos (x) = - 1

Divide both sides by

- 1

- cos (x) = - 1

Divide both sides by

- 1

\frac{- cos ( x )}{- 1} = \frac{- 1}{- 1}

Simplify

cos (x) = 1

cos (x) = 1

General solutions for

cos (x) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

sin (a) = \frac{- 3}{2}

sin (x) = 467

csc (x) = \frac{5}{3}

sin (B) = \frac{( 240.68 \cdot sin ( 21.1 6 ^{\circ} ) )}{207.91}

2 sin (2 x + \frac{π}{4}) = - 1, - 2 π \leq x \leq 2 π

What is the general solution for solvefor x,1-cos(x)=0 ?
The general solution for solvefor x,1-cos(x)=0 is x=2pin