What is the axis x^2+2x-y=3 ?

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axis x^2+2x-y=3

axis

x^{2} + 2 x - y = 3

x = - 1

Solution steps

x^{2} + 2 x - y = 3

Rewrite

x^{2} + 2 x - y = 3

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y^{2} + 6 y - 2 x + 13 = 0

y = 2 \cdot x^{2} + x - 2

- 2 x^{2} - 4 x + y + 70 = 0

y = - 2 (x - 2)^{2} + 7

y > x^{2} - 3