What is the critical f(x)=x^4-4x^2 ?

The critical f(x)=x^4-4x^2 is x=-sqrt(2),x=0,x=sqrt(2)

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critical f(x)=x^4-4x^2

critical points

f (x) = x^{4} - 4 x^{2}

x = - 2, x = 0, x = 2

Solution steps

x^{4} - 4 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 4 x^{2} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

y = x^{2} - 3 x + 2

f (x) = \frac{8 x - 2}{x ^{2} - 2 x - 63}

f (x) = x^{2} + 1, x \leq 0

3 x + 4 y = 5, (3, - 2)

lo g_{3} (x^{2} - 1)

What is the critical f(x)=x^4-4x^2 ?
The critical f(x)=x^4-4x^2 is x=-sqrt(2),x=0,x=sqrt(2)