What is the critical y=x^2-3x+2 ?

The critical y=x^2-3x+2 is x= 3/2

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critical y=x^2-3x+2

critical points

y = x^{2} - 3 x + 2

x = \frac{3}{2}

Solution steps

x^{2} - 3 x + 2

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{3}{2}

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 3 x + 2 : - \infty < x < \infty

All critical points are in domain

x = \frac{3}{2}

f (x) = \frac{8 x - 2}{x ^{2} - 2 x - 63}

f (x) = x^{2} + 1, x \leq 0

3 x + 4 y = 5, (3, - 2)

lo g_{3} (x^{2} - 1)

f (x) = 3 2 x - 1 + 15