What is the domain of log_{3}(x^2-1) ?

The domain of log_{3}(x^2-1) is x 1

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domain of log_{3}(x^2-1)

domain

lo g_{3} (x^{2} - 1)

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

The function domain

x < - 1 or x > 1

f (x) = 3 2 x - 1 + 15

x^{3} + 3 x + 6

f (x) = x^{2} (x - 1) (x + 3)

f (x) = \frac{2 x + 8}{x - 3}

f (x) = x - 3

What is the domain of log_{3}(x^2-1) ?
The domain of log_{3}(x^2-1) is x<-1\lor x>1