What is the perpendicular 3x+4y=5,(3,-2) ?

The perpendicular 3x+4y=5,(3,-2) is y= 4/3 x-6

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perpendicular 3x+4y=5,(3,-2)

perpendicular

3 x + 4 y = 5, (3, - 2)

y = \frac{4}{3} x - 6

Solution steps

Find the line

y = mx + b

perpendicular to

3 x + 4 y = 5

that passes through

(3, - 2)

Find the slope of

3 x + 4 y = 5 : m = - \frac{3}{4}

Compute the slope of the perpendicular line:

m_{p} = \frac{4}{3}

Find the line with slope m=

\frac{4}{3}

and passing through

(3, - 2) : y = \frac{4}{3} x - 6

y = \frac{4}{3} x - 6

lo g_{3} (x^{2} - 1)

f (x) = 3 2 x - 1 + 15

x^{3} + 3 x + 6

f (x) = x^{2} (x - 1) (x + 3)

f (x) = \frac{2 x + 8}{x - 3}

What is the perpendicular 3x+4y=5,(3,-2) ?
The perpendicular 3x+4y=5,(3,-2) is y= 4/3 x-6