extreme f(x)=(-2(x^2-1))/(x^2-4)

Lösung

extrempunkte

f (x) = \frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

Minimum (0, - \frac{1}{2})

Schritte zur Lösung

f^{'} (x) = \frac{12 x}{( x ^{2} - 4 ) ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < - 2,

Absteigend

: - 2 < x < 0,

Ansteigend

: 0 < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = 0

\frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4} : - \frac{1}{2}

Minimum (0, - \frac{1}{2})

e x t re m e f (x, y) = \frac{e ^{2 - x y}}{x + y ^{2}}

e x t re m e f (x) = \frac{- 7}{x ^{2} - 9}

e x t re m e f (x, y) = 2 x^{2} + 3 y^{2} - 4 x - 3 y - 10

e x t re m e f (x, y) = e^{y} - y e^{x}

e x t re m e f (x) = 2 x + cos (2 x), 0 < x < π