What is the extreme f(x)=(log_{10}(x))/x ?

The extreme f(x)=(log_{10}(x))/x is Maximum(e,(log_{10}(e))/e)

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extreme f(x)=(log_{10}(x))/x

extreme

Maximum (e, \frac{lo g _{10} ( e )}{e})

Solution steps

f^{'} (x) = \frac{1 - ln ( x )}{ln ( 10 ) x ^{2}}

Find intervals:

Increasing

: 0 < x < e,

Decreasing

: e < x < \infty

Plug

x = e

into

\frac{lo g _{10} ( x )}{x} : \frac{lo g _{10} ( e )}{e}

Maximum (e, \frac{lo g _{10} ( e )}{e})

What is the extreme f(x)=(log_{10}(x))/x ?
The extreme f(x)=(log_{10}(x))/x is Maximum(e,(log_{10}(e))/e)