What is the integral of 10x^4-2sec^2(x) ?

The integral of 10x^4-2sec^2(x) is 2x^5-2tan(x)+C

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integral of 10x^4-2sec^2(x)

\int 10 x^{4} - 2 sec^{2} (x) d x

2 x^{5} - 2 tan (x) + C

Solution steps

\int 10 x^{4} - 2 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 x^{4} d x - \int 2 sec^{2} (x) d x

\int 10 x^{4} d x = 2 x^{5}

\int 2 sec^{2} (x) d x = 2 tan (x)

= 2 x^{5} - 2 tan (x)

Add a constant to the solution

= 2 x^{5} - 2 tan (x) + C

\frac{4}{x ^{2}}

\frac{9}{x}

x^{2} + x y - \frac{y ^{2}}{4} = 1

f (x) = (5 x + 2 x^{2})^{2}

\frac{4}{s + 3}

What is the integral of 10x^4-2sec^2(x) ?
The integral of 10x^4-2sec^2(x) is 2x^5-2tan(x)+C