What is the tangent of 9/x ?

The tangent of 9/x is y=-9/(a_{0)^2}x+(18)/(a_{0)}

Popular >

tangent of 9/x

tangent of

\frac{9}{x}

y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{9}{a _{0}})

Find the slope of

y = \frac{9}{x} : \frac{d y}{d x} = - \frac{9}{x ^{2}}

Compute the slope of

y = \frac{9}{x}

x = a_{0} : m = - \frac{9}{a _{0}^{2}}

Find the line with slope m=

- \frac{9}{a _{0}^{2}}

and passing through

(a_{0}, \frac{9}{a _{0}}) : y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

y = - \frac{9}{a _{0}^{2}} x + \frac{18}{a _{0}}

x^{2} + x y - \frac{y ^{2}}{4} = 1

f (x) = (5 x + 2 x^{2})^{2}

\frac{4}{s + 3}

x \to \infty lim (- x e^{- x^{2}} 2 - e^{- x^{2}})

\frac{d v}{d y} + 2 \cdot v = 4 e^{- y}