What is the slope of x^2+xy-(y^2)/4 =1 ?

The slope of x^2+xy-(y^2)/4 =1 is (-4x-2y)/(2x-y)

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slope of x^2+xy-(y^2)/4 =1

slope

x^{2} + x y - \frac{y ^{2}}{4} = 1

\frac{- 4 x - 2 y}{2 x - y}

Solution steps

x^{2} + x y - \frac{y ^{2}}{4} = 1

Use implicit differentiation to find the slope of

x^{2} + x y - \frac{y ^{2}}{4} = 1

Implicit Derivative

\frac{d y}{d x}

x^{2} + x y - \frac{y ^{2}}{4} = 1 : \frac{- 4 x - 2 y}{2 x - y}

\frac{- 4 x - 2 y}{2 x - y}

f (x) = (5 x + 2 x^{2})^{2}

\frac{4}{s + 3}

x \to \infty lim (- x e^{- x^{2}} 2 - e^{- x^{2}})

\frac{d v}{d y} + 2 \cdot v = 4 e^{- y}

\int_{- 8}^{3} ∣ x ∣ + 1 d x

What is the slope of x^2+xy-(y^2)/4 =1 ?
The slope of x^2+xy-(y^2)/4 =1 is (-4x-2y)/(2x-y)