What is the tangent of 4/(x^2) ?

The tangent of 4/(x^2) is y=-8/(a_{0)^3}x+(12)/(a_{0)^2}

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tangent of 4/(x^2)

tangent of

\frac{4}{x ^{2}}

y = - \frac{8}{a _{0}^{3}} x + \frac{12}{a _{0}^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{4}{a _{0}^{2}})

Find the slope of

y = \frac{4}{x ^{2}} : \frac{d y}{d x} = - \frac{8}{x ^{3}}

Compute the slope of

y = \frac{4}{x ^{2}}

x = a_{0} : m = - \frac{8}{a _{0}^{3}}

Find the line with slope m=

- \frac{8}{a _{0}^{3}}

and passing through

(a_{0}, \frac{4}{a _{0}^{2}}) : y = - \frac{8}{a _{0}^{3}} x + \frac{12}{a _{0}^{2}}

y = - \frac{8}{a _{0}^{3}} x + \frac{12}{a _{0}^{2}}

\frac{9}{x}

x^{2} + x y - \frac{y ^{2}}{4} = 1

f (x) = (5 x + 2 x^{2})^{2}

\frac{4}{s + 3}

x \to \infty lim (- x e^{- x^{2}} 2 - e^{- x^{2}})

What is the tangent of 4/(x^2) ?
The tangent of 4/(x^2) is y=-8/(a_{0)^3}x+(12)/(a_{0)^2}