What is the derivative of x^2+2x-1 ?

The derivative of x^2+2x-1 is 2x+2

What is the first derivative of x^2+2x-1 ?

The first derivative of x^2+2x-1 is 2x+2

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\frac{d}{d x} (x^{2} + 2 x - 1)

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

- 4 \frac{d y}{d x} + 12 x^{2} = 0

y = 2 x - 3

y = x + 6, y = x^{3}, x = 0

\frac{d}{d x} (a^{- x})

\frac{d}{d t} (3 t + 1)

What is the derivative of x^2+2x-1 ?
The derivative of x^2+2x-1 is 2x+2
What is the first derivative of x^2+2x-1 ?
The first derivative of x^2+2x-1 is 2x+2