What is the d/(dt)(sqrt(3t+1)) ?

The d/(dt)(sqrt(3t+1)) is 3/(2sqrt(3t+1))

What is the first d/(dt)(sqrt(3t+1)) ?

The first d/(dt)(sqrt(3t+1)) is 3/(2sqrt(3t+1))

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\frac{d}{d t} (3 t + 1)

\frac{3}{2 3 t + 1}

Solution steps

\frac{d}{d t} (3 t + 1)

Apply the chain rule:

\frac{1}{2 3 t + 1} \frac{d}{d t} (3 t + 1)

= \frac{1}{2 3 t + 1} \frac{d}{d t} (3 t + 1)

\frac{d}{d t} (3 t + 1) = 3

= \frac{1}{2 3 t + 1} \cdot 3

Simplify

\frac{1}{2 3 t + 1} \cdot 3 : \frac{3}{2 3 t + 1}

= \frac{3}{2 3 t + 1}

\int - t ln (t) d t

x^{2}, at x = 0

\frac{\partial}{\partial y} (x^{3} y z^{2})

\int [\frac{4}{16 x ^{2} + 1}] d x

f (x) = x^{2} - 5 x + 5, (6, 11)

What is the d/(dt)(sqrt(3t+1)) ?
The d/(dt)(sqrt(3t+1)) is 3/(2sqrt(3t+1))
What is the first d/(dt)(sqrt(3t+1)) ?
The first d/(dt)(sqrt(3t+1)) is 3/(2sqrt(3t+1))