What is (\partial)/(\partial y)(x^3yz^2) ?

The answer to (\partial)/(\partial y)(x^3yz^2) is x^3z^2

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(\partial)/(\partial y)(x^3yz^2)

\frac{\partial}{\partial y} (x^{3} y z^{2})

x^{3} z^{2}

Solution steps

\frac{\partial}{\partial y} (x^{3} y z^{2})

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{3} z^{2} \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= x^{3} z^{2} \cdot 1

Simplify

= x^{3} z^{2}

\int [\frac{4}{16 x ^{2} + 1}] d x

f (x) = x^{2} - 5 x + 5, (6, 11)

\frac{\partial}{\partial s} (s + t)

\frac{d}{d x} ((x - 3)^{\frac{2}{3}})

\int \frac{2 x}{4 - x ^{4}} d x

What is (\partial)/(\partial y)(x^3yz^2) ?
The answer to (\partial)/(\partial y)(x^3yz^2) is x^3z^2