What is the first derivative of y=2x-3 ?

The first derivative of y=2x-3 is 2

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derivative of y=2x-3

derivative of

y = 2 x - 3

2

Solution steps

\frac{d}{d x} (2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 - 0

Simplify

= 2

y = x + 6, y = x^{3}, x = 0

\frac{d}{d x} (a^{- x})

\frac{d}{d t} (3 t + 1)

\int - t ln (t) d t

x^{2}, at x = 0